Let a1,a2,a3,…,a49 be in A.P. such that 12∑k=0a4k+1=416 and a9+a43 – InterviewSolution

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1.	Let a1,a2,a3,…,a49 be in A.P. such that 12∑k=0a4k+1=416 and a9+a43=66. If a21+a22+…+a217=140m, then m is equal to:
Answer» Let $a_{1}, a_{2}, a_{3}, \dots, a_{49}$ be in $A . P .$ such that $12 \sum k = 0 a_{4 k + 1} = 416$ and $a_{9} + a_{43} = 66.$ If $a_{1}^{2} + a_{2}^{2} + \dots + a_{17}^{2} = 140 m$ , then $m$ is equal to:

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