Let abc be a three digit number. Then abc + bca + cab is not divisible

1.	Let abc be a three digit number. Then abc + bca + cab is not divisible by(a) a + b + c (b) 3 (c) 37 (d) 9
Answer» The correct answer is option (d) 9 Explanation: By simplifying the general form of abc, bca and cab, we will get = abc+bca+cab = 111(a+b+c) Hence, abc+bca+cab is divisible by 111 and also it is divisible by the factors of 111. Here, 3 and 7 are the factors of 111, and a+b+c is also a factor of 111(a+b+c). But 9 is not the factor of 111.

Let abc be a three digit number. Then abc + bca + cab is not divisible by(a) a + b + c (b) 3 (c) 37 (d) 9

Answer»

The correct answer is option (d) 9

Explanation:

By simplifying the general form of abc, bca and cab, we will get

= abc+bca+cab = 111(a+b+c)

Hence, abc+bca+cab is divisible by 111 and also it is divisible by the factors of 111.

Here, 3 and 7 are the factors of 111, and a+b+c is also a factor of 111(a+b+c).

But 9 is not the factor of 111.