1.

Let ABCD be a parallelogram whose equations for the diagonals AC and BD are x+2y=3 and 2x+y=3, respectively. The length of side AB is equal to

Answer»

`2sqrt(58)//3`
`4sqrt(58)//9`
`3sqrt(58)//9`
`4sqrt(58)//9`

Solution :`"cos" (pi-theta) = (AP^(2) + PB^(2)-AB^(2))/(2AP xx PB)`
`"or " -(4)/(5) = (4+(100//9)-AB^(2))/(2 xx 2 xx (10//3))`
`"or " AB = (2sqrt(58))/(3)`


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