1.

Let ABCD be a square with sides of unit lenght. Points E and F are taken on sides AB and AD, respectively,so that AE=AF. Let P be a point inside the squre ABCD. The value of (PA)^2-(PB)^2+(PC)^2-(PD)^2 is equal to

Answer»

3
2
1
0

Solution :
`(PA)^2-(PB)^2+(PC)^2-(PD)^2`
`=(alpha^2+gamma ^2)-(alpha^2+delta^2)+(delta^2+beta^2)-(gamma^2+beta^2)=0`


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