1.

Let ADbe theanglebisector ofangle AofDelta ABCsuchthatAD= alphaAB + betaAC ,then

Answer»

`ALPHA =(|AB|)/(|AB|+|AC|),beta =(|AC|)/(|AB|+|AC|)`
`alpha =(|AB|+|AC|)/(|AB|),beta =(|AB|+|AC|)/(|AC|)`
`alpha =(|AC|)/(|AB|+|AC|), beta =(|AB|)/(|AB|+|AC|)`
`alpha =(|AB|)/(|AC|), beta =(|AC|)/(|AB|)`

SOLUTION :Clearly ,AD dividesBCin THERATIO`AB:AC`.
`thereforeAD =(|AB|AC||AC|AB)/(|AB|+|AC|)`
`implies |AD|= alpha AB + beta AC , ` where
` alpha =(|AC|)/(|AB|+|AC|)and beta =(|AB|)/(|AB|+|AC|)`


Discussion

No Comment Found

Related InterviewSolutions