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Let all chords of parabola `y^(2)=x+1` which subtends right angle at `(1,sqrt(2))` passes through `(a,b)` then the value of `a+b^(2)` is |
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Answer» Correct Answer - 4 Shifting origin at `(1,sqrt(2))` `(Y+2sqrt(2))^(2)=X+1+1,y=Y+sqrt(2),x=X+1` `Y^(2)+(2sqrt(2)Y-X)((Y-mX)/C)=0` `1+(2sqrt(2))/C+m/C=0` `C+m+2sqrt(2)=0` `Y=mx-=m-2sqrt(2)` `y-sqrt(2)=m(x-1)-m-2sqrt(2)` it is passes through `(a,b)AAm` `impliesa=2` and `b=-sqrt(2)` |
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