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Let alpha and beta be two real roots of the equation 5cot^2x-3cotx-1=0 , then cot^2 (alpha+beta) = |
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Answer» 2 `cot(alpha+beta)=(cot alpha cot beta-1)/(cot alpha+cot beta)=(-1/5-1)/(3/5)` `=-6/3 =-2 rArr cot^2 (alpha+beta)=4` |
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