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Let alpha and beta be two real roots of the equation 5cot^2x-3cotx-1=0 , then cot^2 (alpha+beta) =

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Solution :`cot ALPHA + cot BETA =3/5 cot alpha .cot beta = -1/5`
`cot(alpha+beta)=(cot alpha cot beta-1)/(cot alpha+cot beta)=(-1/5-1)/(3/5)`
`=-6/3 =-2 rArr cot^2 (alpha+beta)=4`


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