Let An=(34)−(34)2+(34)3−...+(−1)n(34)n and Bn=1−An. Then, the – InterviewSolution

1.	Let An=(34)−(34)2+(34)3−...+(−1)n(34)n and Bn=1−An. Then, the least odd natural number p, so that Bn>An, for all n≥p, is :
Answer» Let $A_{n} = (\frac{3}{4}) - {(\frac{3}{4})}^{2} + {(\frac{3}{4})}^{3} - . . . + (- 1)^{n} {(\frac{3}{4})}^{n}$ and $B_{n} = 1 - A_{n}$ . Then, the least odd natural number $p$ , so that $B_{n} > A_{n}$ , for all $n \geq p$ , is :

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