Saved Bookmarks
| 1. |
Let {an} be a non - constant arithmetic progression with a1=1 and for any n≥1, the value a2n+a2n−1+⋯+an+1an+an−1+⋯a1 remains constant. Then, a15 will be? |
|
Answer» Let {an} be a non - constant arithmetic progression with a1=1 and for any n≥1, the value a2n+a2n−1+⋯+an+1an+an−1+⋯a1 remains constant. |
|