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| 1. |
Let `B_(P)` and `B_(Q)` be the magnetic field produced by the wire `P` and `Q` which are placed symmetrically in a rectangular loop `ABCD` as shown in figure.Current in wire `P` is `I` directed inward and in `Q` is `2I` directed outwards.if `int_(A)^(B)vecB_(Q).vecdl=2mu_(0)` tesla meter,`int_(D)^(A)vecB_(P).vecdl=-2mu_(0)` tesla meter,&`int_(A)^(B)vecB_(P).vecdl=-mu_(0)` tesla meter tesla meter the value of `I` will be: A. `8 A`B. `4 A`C. `5 A`D. `6 A` |
| Answer» Correct Answer - D | |