1.

Let be a binary operation on the set Q of all rational numbers given as a * b = (2a - b)2 for all a, b ∈ Q. Find 3 * 5 and 5 * 3. Is 3 * 5 = 5 * 3?

Answer»

To find: 3*5 and 5*3 

Given: a*b = (2a - b)2 

⇒ 3*5 = (6 - 5)2 = 1 

Now 5*3 = (10 - 3)2 = 49 

⇒ 3*5 is not equal to 5*3



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