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Let ** be a binary operation on the set Q of rational numbers as followsa**b=a-b. Check whether * is commutative and associative |
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Answer» SOLUTION :SINCE `1-2ne2-1, 1**2 ne 2**1` `therefore ** ` is not COMMUTATIVE Since `(2-4)-5ne2-(4-5), `(2**4)**5 ne 2**(4**5)` `therefore **` is not associative `**` is not commutative, not associative |
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