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Let ** be a binary operation on the set Q of rational numbers as followsa**b=a-b. Check whether * is commutative and associative

Answer»

SOLUTION :SINCE `1-2ne2-1, 1**2 ne 2**1`
`therefore ** ` is not COMMUTATIVE
Since `(2-4)-5ne2-(4-5),
`(2**4)**5 ne 2**(4**5)`
`therefore **` is not associative
`**` is not commutative, not associative


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