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Let * be a binary operation on the set Q of rational numbers as follows. Find which of the binary operations are commutative and which are associative. a * b = (a – b)2 |
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Answer» a * b = (a – b)2 = (b – a)2= b * a hence * is not commutative (a * b) * c = (a – b)2 * c = ((a-b)2 – c)2 = (a – b)4+ c2 – 2c (a – b)2 a*(b * c) = a* (b – c)2 = [a -(b – c)]2 = a2 + (b – c)2 – 2a (b – c)2 hence not associative |
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