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Let C _(1) and C _(2) be the centres of the circles x ^(2) + y ^(2) - 2x - 2y -2 =0 and x ^(2) +y ^(2) - 6x + 14=0 respectively. If P and Q are the points of intersection of these circles, then the area (in sq. units) of the quadrilateral PC _(1) QC_(2) is: |
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Answer» 8 |
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