Let C1 and C2 be the centres of the circles x2+y2−2x−2y−2=0 and – InterviewSolution

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1.	Let C1 and C2 be the centres of the circles x2+y2−2x−2y−2=0 and x2+y2−6x−6y+14=0 respectively. If P and Q are the points of intersection of these circles, then the area (in sq. units) of the quadrilateral PC1QC2 is :
Answer» Let $C_{1}$ and $C_{2}$ be the centres of the circles $x^{2} + y^{2} - 2 x - 2 y - 2 = 0$ and $x^{2} + y^{2} - 6 x - 6 y + 14 = 0$ respectively. If $P$ and $Q$ are the points of intersection of these circles, then the area (in sq. units) of the quadrilateral $P C_{1} Q C_{2}$ is :

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