Let complex numbers α and 1¯α lie on circles (x−x0)2+(y−y0)2=r2 – InterviewSolution

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1.	Let complex numbers α and 1¯α lie on circles (x−x0)2+(y−y0)2=r2 and (x−x0)2+(y−y0)2=4r2,respectively. If z0=x0+iy0 satisfies the equation 2\|z0\|2=r2+2, then \|α\|=
Answer» Let complex numbers $α$ and $\frac{1}{¯ α}$ lie on circles $(x - x_{0})^{2} + (y - y_{0})^{2} = r^{2} and (x - x_{0})^{2} + (y - y_{0})^{2} = 4 r^{2},$ respectively. If $z_{0} = x_{0} + i y_{0}$ satisfies the equation $2 \| z_{0} \|^{2} = r^{2} + 2, then \| α \| =$

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