1.

Let d + 2(2b + c) = 19. What will be the remainder when the 4-digit number abcd is divided by 8?1. 22. 53. 04. 3

Answer» Correct Answer - Option 4 : 3

Given:

d + 2(2b + c) = 19 

Concept used :

Divisibility rule of 8 

A number is divisible by 8 if last 3 digits are divisible by 8 

Calculations :

abcd = 1000a + 100b + 10c + d

For abcd to be divisible by 8, 100b + 10c + d must be divisible by 8 

(100b + 10c + d)/8 = [100b + 10c + 19 - 2(2b + c)]/8            [d = 19 - 2(2b + c)]

⇒ (100b + 10c - 4b - 2c + 19)/8 

⇒ (96b + 8c + 19)/8 

⇒ (96b + 8c)/8)  + 19/8 

We can see that 96b + 8c is divisible by 8 and only 19 will give remainder 

Remainder = 3 

∴ Remainder will be 3 when abcd is divided by 8



Discussion

No Comment Found

Related InterviewSolutions