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Let D, E and F be the middle points of the sides BC,CA and AB respectively of a triangle ABC. Then, AD + BE + CF equals to |
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Answer» Solution :LET the position vectors A, B, C be a, b and c respectively . Then the position vectors of mid-points D, E and F are ` (b+c)/(2)`,(c+a)/( 2) and(a+b) /(2)`repectively . Now `AD +BE +CF` `={(b+c)/(2)-a}+{(c+a)/(2)-b}+{(a+b)/(2)-c )}=0` |
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