Let d∈R, and A=⎡⎢⎣−24+d(sinθ)−21(sinθ)+2d5(2sinθ)−d( – InterviewSolution

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1.	Let d∈R, and A=⎡⎢⎣−24+d(sinθ)−21(sinθ)+2d5(2sinθ)−d(−sinθ)+2+2d⎤⎥⎦, θ∈[0,2π]. If the minimum value of det(A) is 8, then a value of d is:
Answer» Let $d \in R$ , and $A = ⎡ ⎢ ⎣ \begin{matrix} - 2 & 4 + d & (sin θ) - 2 1 & (sin θ) + 2 & d 5 & (2 sin θ) - d & (- sin θ) + 2 + 2 d \end{matrix} ⎤ ⎥ ⎦$ , $θ \in [0, 2 π] .$ If the minimum value of $d e t (A)$ is $8$ , then a value of $d$ is:

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