1.

Let ddxF(x)=(esinxx), where x>0. If 4∫13xesinx3dx=F(k)−F(1), then the possible value of k is

Answer» Let ddxF(x)=(esinxx), where x>0. If 413xesinx3dx=F(k)F(1), then the possible value of k is


Discussion

No Comment Found

Related InterviewSolutions