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Let ddxF(x)=(esinxx), where x>0. If 4∫13xesinx3dx=F(k)−F(1), then the possible value of k is |
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Answer» Let ddxF(x)=(esinxx), where x>0. If 4∫13xesinx3dx=F(k)−F(1), then the possible value of k is |
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