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Let DeltaABC be inscribedin a circle having radius unity. The three internalbisectorsof the angles A, B and C are extended to intersect the circumcircleof DeltaABC at A_(1)B_(1) and C_(1) respectively. Then (A A_(1)"cos"(A)/(2)BB_(1)"cos"(B)/(2)+C C_(1)"cos"(C)/(2))/(sinA+sinB+sinC)= |
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