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Let ƒ and g be differentiable functions on R such that fog is the identity function. If for some a, b ∈ R, g'(a) = 5 and g(a) = b, then ƒ'(b) is equal to : (1) 2/5 (2) 1 (3) 1/5 (4) 5 |
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Answer» Answer is (3) 1/5 f(g(x)) = x f'(g(x)) g'(x) = 1 put x = a f'(b) g'(a) = 1 f'(b) = 1/5 Answer is (3) 1/5 f(g(x)) = x f'(g(x)).g'(x) = 1 x = a f'(g(a)) - g'(a) = 1 f'(b) = 1/5 |
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