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Let f be a positive function Let I1=∫k1−kx f{x(1−x)}dx I2=∫k1−kf{x(1−x)}dx where 2k−1>0,. If I2=pI1 then the value of p is |
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Answer» Let f be a positive function Let I1=∫k1−kx f{x(1−x)}dx I2=∫k1−kf{x(1−x)}dx where 2k−1>0,. If I2=pI1 then the value of p is |
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