Saved Bookmarks
| 1. |
Let f: defined from `(1//4,oo) to R^(+) as, f(x)=log_(1//4)(x-(1)/(4))+(1)/(2)log_(4)(16x^(2)-8x+1)` Statement-1: f(x) is neither injective nor surjective . Statement-1: f(x) is a constant function.A. Statement-1 is true, statement -2 is true and statement -2 is correct explantion for statement-1.B. Statement-1 is true, statement -2 is true and statement -2 is NOT correct explantion for statement-1.C. Statement-1 is true, statement-2 is falseD. Statement-1 is false, statement-2 is true |
|
Answer» B `f(x)=log_(1//4)(x-(1)/(4))+(1)/(2) log_(4)16+(1)/(2) log_(4)(x^(2)-(x)/(2)+(1)/(16))(x gt(1)/(4))` `=log_(1//4)(x-(1)/(4))+1+log_(4)(x-(1)/(4))` `=-log_(4)(x-(1)/(4))+log_(4)(x-(1)/(4))+1` `=1 implies ` f is constant hence f is many one as well into. Also range is a singelton `implies` f is constant but a constant function can be any thing `implies` not the explanation. |
|