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Let f, f′, f′′ be continuous in [0,ln2] and f(0)=0, f′(0)=3,f(ln2)=6,f′(ln2)=4 and ∫ln20e−2xf(x)dx=3,then∫ln20e−2xf′′(x)dx is |
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Answer» Let f, f′, f′′ be continuous in [0,ln2] and f(0)=0, f′(0)=3,f(ln2)=6,f′(ln2)=4 and ∫ln20e−2xf(x)dx=3,then∫ln20e−2xf′′(x)dx is |
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