1.

Let f,g : [-1,2] tobe continuous functions which are twice differentiable on the interval (-1,2). Let the values of f and g at the pointsand 2 be as given in the following table: In each of the intervals(-1,0) and (0, 2) the function (f-3g) never vanishes. Then the correct statements(s) is(are) :

Answer»

f'(X)-3g'(x)=0 has exactly three solution in`(-1,0) CUP (0,2)`
`f'(x)-3g'(x)=0` has exactly one solution in(-1,0)
f'(x)-3g'(x)=0 has exactly one solution in (0, 2)
f'(x)-3g'(x)=0 has exactly TWO solutions INAND exactly two solutions in (0, 2)

Answer :B::C


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