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Let f,g : [-1,2] tobe continuous functions which are twice differentiable on the interval (-1,2). Let the values of f and g at the pointsand 2 be as given in the following table: In each of the intervals(-1,0) and (0, 2) the function (f-3g) never vanishes. Then the correct statements(s) is(are) : |
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Answer» f'(X)-3g'(x)=0 has exactly three solution in`(-1,0) CUP (0,2)` |
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