Let f,g:R→R be two functions. If 4x−y−8=0 and 12x+y+26=0 are – InterviewSolution

1.	Let f,g:R→R be two functions. If 4x−y−8=0 and 12x+y+26=0 are the tangents to the graph of the functions f(x) and g(x) at x=1 and x=−3 respectively, and h(x)=(g(x+f(x)))2, then −h′(1)100 is equal to
Answer» Let $f, g : R \to R$ be two functions. If $4 x - y - 8 = 0$ and $12 x + y + 26 = 0$ are the tangents to the graph of the functions $f (x)$ and $g (x)$ at $x = 1$ and $x = - 3$ respectively, and $h (x) = (g (x + f (x)))^{2},$ then $- \frac{h^{'} (1)}{100}$ is equal to

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