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Let `f: IvecI`be a function `(I`is set of integers`)`such that `f(0)=1,f(f(n)=f(f(n+2)+2)=ndot`then`f(3)=0`b. `f(2)=0`c. `f(3=-2)`d. `f`is many one functionA. `f(3)=0`B. `f(2)=0`C. `f(3)=-2`D. f is many -one function |
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Answer» Correct Answer - C Given that `f(f(n)) = n and " (i)"` f(0) = 1 Put n = 0, we get `f(f(0))=0 or f(1)=0` Also given that `f(f(n+2)+2)=n" (ii)"` Put `n=-1`, we get `f(f(1)+2)=-1 or f(0+2)=-1 or f(2)=-1` For f(3), put n= -2 in (ii) `therefore" "f(f(0)+2)=-2` `"or "f(1+2)=-2` `"or "f(3)=-2` |
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