InterviewSolution
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Let f(n)=∣∣∣∣∣nn+1n+2nPnn+1Pn+1n+1Pn+2nCnn+1Cn+1n+1Cn+2∣∣∣∣∣Then, f(n) is divisible by |
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Answer» Let f(n)=∣∣ |
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