1.

Let f:R→R be a differentiable function such that f(x)=x2+x∫0e−tf(x−t)dt. Then, the value of 1∫0f(x)dx is

Answer»

Let f:R→R be a differentiable function such that f(x)=x2+x∫0e−tf(x−t)dt. Then, the value of 1∫0f(x)dx is




Discussion

No Comment Found