Let f : R → R be defined by f(x) = 3x2 – 5 and g : R → R by gx=x – InterviewSolution

1.	Let f : R → R be defined by f(x) = 3x2 – 5 and g : R → R by gx=xx2+1. Then (gof) (x) is(a) 3x2−59x4−30x2+26(b) 3x2−59x4−6x2+26(c) 3x2x4+2x2−4(d) 3x29x4+30x2−2
Answer» Let f : R → R be defined by f(x) = 3x² – 5 and g : R → R by $g (x) = \frac{x}{x^{2} + 1} .$ Then (gof) (x) is (a) $\frac{3 x^{2} - 5}{9 x^{4} - 30 x^{2} + 26}$ (b) $\frac{3 x^{2} - 5}{9 x^{4} - 6 x^{2} + 26}$ (c) $\frac{3 x^{2}}{x^{4} + 2 x^{2} - 4}$ (d) $\frac{3 x^{2}}{9 x^{4} + 30 x^{2} - 2}$

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