1.

Let f:S→S where S=(0,∞) be a twice differentiable function such that f(x+1)=xf(x). If g:S→R be defined as g(x)=logef(x), then the value of |g′′(5)−g′′(1)| is equal to :

Answer»

Let f:SS where S=(0,) be a twice differentiable function such that f(x+1)=xf(x). If g:SR be defined as g(x)=logef(x), then the value of |g′′(5)g′′(1)| is equal to :




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