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Let f(x) = √(1 + x2) then (1) f(xy) = f(x),f(y) (2) f(xy) ≥ f(x),f(y) (3) f(xy) ≤ f(x).f(y) (4) None of these |
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Answer» (3) f(xy) ≤ f(x).f(y) √(1 + x2y2) ≤ √(1 + x2) √(1 + y2) ⇒ f(xy) ≤ f(x).f(y) |
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