1.

Let f(x)=(27−2x)1/3−39−3(243+5x)1/5,x≠0. If f(x) is continuous at x=0, then the value of f(0) is

Answer»

Let f(x)=(272x)1/3393(243+5x)1/5,x0. If f(x) is continuous at x=0, then the value of f(0) is



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