1.

Let f(x)=3^(alphax)+3^(betax), where alpha ne beta and 3f'(x)log_(3)e=2f(x)+f''(x)(log_(3)e)^(2) for all x. Then the value of alpha+beta is :

Answer»


Solution :`f(X)=3^(alphax)+3^(betax)`
`f'(x)=alpha3^(alphax)ln3+3^(BETA x)beta ln 3`
`f''(x)=alpha^(2)3^(alphax)(ln3)^(2)+3^(betax)beta^(2)(ln3)^(2)`
PUT it in given CONDITION and solve.


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