1.

Let {:f(x)= {(abs(x+1):,xlt1),(1-x:,x le 1):} and {:f(x)= {(x-2:, xlt0),(x+3:, x ge0):}. Then the function h - fg is given by :

Answer»

`{:{(x^2+x+2:, xlt-1),(x^2-x-2:,-1le x lt 0),(x^2+ 4x+3:,0lexlt1),(-x^2 -2X +3:, xgt1):}`
`{:{(-x^2 + x +2 :,x lt-1),(x^2 - x -2 :,-1 LE x LT0),(x^2-4x +3:,0 le xlt 1),(-x^2 - 2x + 3:,x ge1):}`
`{:{(-x^2+x+2:,xlt-1),(x^2-x-2:,-1 le xlt0),(x^2 + 4x +3 :, 0 le x le 1),(-x^2 - 2x +3:, x ge 1):}`
None of these

Answer :C


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