Let f(x)=⎧⎪⎪⎪⎪⎪⎨⎪⎪⎪⎪⎪⎩acot−1(b+x4),−23< – InterviewSolution

1.	Let f(x)=⎧⎪⎪⎪⎪⎪⎨⎪⎪⎪⎪⎪⎩acot−1(b+x4),−23<x<02,x=0ln(1−cx)x,0<x<23.If the function f is differentiable at x=0, then the value of b2−2a+c6 is
Answer» Let $f (x) = ⎧ ⎪⎪⎪⎪⎪ ⎨ ⎪⎪⎪⎪⎪ ⎩ \begin{matrix} a {cot}^{- 1} (\frac{b + x}{4}), & \frac{- 2}{3} < x < 0 2, & x = 0 \frac{ln (1 - c x)}{x}, & 0 < x < \frac{2}{3} \end{matrix} .$ If the function $f$ is differentiable at $x = 0,$ then the value of $b^{2} - 2 a + c^{6}$ is

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