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Let f(x) be a differentiable function in the interval (0,2) , then the value of int_0^2 f(x) dx is : |
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Answer» F( c) for some `c in (0,2)` Now applying lagrange.s mean value theorem in (0,2) ` RARR (g(2) - g(0))/(2-0) = g.(c ) `, where `c in (0,2) rarr int_0^2 f(x)dx = 2f(c ) `, where `c in (0,2)`. |
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