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Let f(x) be a polynomial function of second degree and f(1) = f(-1). If a, b, c are in AP, then f'(a), f'(b), f'(c) are in:1. GP2. HP3. AGP4. AP |
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Answer» Correct Answer - Option 4 : AP Concept: Arithmetic Progression (AP): The series of numbers where the difference of any two consecutive terms is the same, is called an Arithmetic Progression.
Geometric Progression (GP): The series of numbers where the ratio of any two consecutive terms is the same, is called a Geometric Progression.
Harmonic Progression (HP): The series of numbers where the reciprocals of the terms are in Arithmetic Progression, is called a Harmonic Progression.
Calculation: Let's say that the second degree polynomial is f(x) = px2 + qx + r. From the given information: f(1) = f(-1) ⇒ p(1)2 + q(1) + r = p(-1)2 + q(-1) + r ⇒ p + q = p - q ⇒ 2q = 0 ⇒ q = 0 ∴ f(x) = px2 + 0(x) + r ⇒ f(x) = px2 + r And, f'(x) = 2px. Now, f'(a) = 2pa, f'(b) = 2pb and f'(c) = 2pc. Since a, b and c are in AP, we have: 2b = a + c. Multiplying by 2p, we get: (2p)2b = (2p)a + (2p)c ⇒ 2(2pb) = 2pa + 2pc ⇒ 2pa, 2pb and 2pc are in AP. ⇒ f'(a), f'(b) and f'(c) are in AP. |
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