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Let f(x)=∣∣sin−1(sinx)∣∣−(π−x2). Then number of solutions of equation f(x)=0 in x∈[−π,π] is |
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Answer» Let f(x)=∣∣sin−1(sinx)∣∣−(π−x2). Then number of solutions of equation f(x)=0 in x∈[−π,π] is |
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