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Let `f(x)=(sin^(2)pix)/(1+pi^(x)).` Then, `int[f(x)+f(-x)]dx` is equal to |
Answer» Correct Answer - B (b) `f(x)+f(-x)=(sin^(2)pix)/(1+pi^(x))+(sin^(2)(-pix))/(1+pi^(-x))` `=(sin^(2)pix)/(1+pi^(x))+((sin^(2)pix)pi^(x))/(pi^(x)+1)` `=sin^(2)pix=(1-cos 2pix)/(2)` `therefore int[f(x)+f(-x)]dx=int[(1-cos 2pix)/(2)]dx` `=(1)/(2)xx-(sin 2pix)/(4pi)+C` |
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