Let f(x)=(sin(tan−1x)+sin(cot−1x))2−1, where |x|>1. If dydx=12dd – InterviewSolution

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1.	Let f(x)=(sin(tan−1x)+sin(cot−1x))2−1, where \|x\|>1. If dydx=12ddx(sin−1(f(x))) and y(√3)=π6, then y(−√3) is equal to:
Answer» Let $f (x) = {(sin ({tan}^{- 1} x) + sin ({cot}^{- 1} x))}^{2} - 1$ , where $\| x \| > 1$ . If $\frac{d y}{d x} = \frac{1}{2} \frac{d}{d x} ({sin}^{- 1} (f (x)))$ and $y (\sqrt{3}) = \frac{π}{6}$ , then $y (- \sqrt{3})$ is equal to:

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