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Let f(x)=sinx+|cosx|−∣∣sinx−|cosx|∣∣, x ϵ(0,2π) then the number of points of non-differentiability of f(x) is |
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Answer» Let f(x)=sinx+|cosx|−∣∣sinx−|cosx|∣∣, x ϵ(0,2π) then the number of points of non-differentiability of f(x) is |
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