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Let `f(x)={(|x-1|+|x-2|, ,, 2ge1),(x, ,, xlt1):}` and `g(x)={("max"{f(t):x-1letlex}, :, 0lt xlt 2),(-x+3, :, 2ltxle3):}` then number of points in`[0,3]` where `g(x)` is not differentiable is/are____ |
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Answer» Correct Answer - 2 `g(x)= {(x, :, 0lexle1),(1, :, 1lexle2),(-x+3, :, xgt2):}` |
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