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Let `f(x)={(x^(2)-4x+3",",x lt 3),(x-4",",x ge 3):}`and `g(x)={(x-3",",x lt 4),(x^(2)+2x+2",",x ge 4):}`. Describe the function `f//g` and find its domain. |
Answer» Correct Answer - `(f(x))/(g(x))={((x^(2)-4x+3)/(x-3)",",x lt 3),((x-4)/(x-3)",",3lt x lt 4),((x-4)/(x^(2)+2x+2)",",x ge 4):} ` `f(x)={(x^(2)-4x+3",",x lt 3),(x-4",",x ge 3):}` `={(x^(2)-4x+3",",x lt 3),(x-4",",3le x lt 4),(x-4",",x ge 4):} " (1)" ` `g(x)={(x-3",",x lt 4),(x^(2)+2x+2",",x ge 4):}` `={(x-3",",x lt 3),(x-3",",3 le x lt 4),(x^(2)+2x+2",",x ge 4):} " (2)" ` From (1) and (2), we have `(f(x))/(g(x))={((x^(2)-4x+3)/(x-3)",",x lt 3),((x-4)/(x-3)",",3lt x lt 4),((x-4)/(x^(2)+2x+2)",",x ge 4):} ` Clearly, `f(x)//g(x)` is not defined at `x=3`. Hence, the domain is `R-{3}.` |
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