1.

Let f(x) ={{:(x^(2)+a, 0 le x lt1),( 2x+b, ale x le 2):} andg(x) ={{:(3x+b,0 le xlt1),( x^(3), 1le x le 2):} if (df)/(dg) exists at x=1, then

Answer»

a=-1
b=-2
`((df)/(DG))_(x=1)=2//3`
`a=+-1, b=+- 2`

ANSWER :A::B::C


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