1.

Let `f(x) =x^(2).` Then dom (f ) and range (f ) are respectivelyA. R and RB. `R^(+) " and " R^(+)`C. `R " and " R^(+)`D. `R " and " R-{0}`

Answer» Correct Answer - C
f(x) `=x^(2) ` is defined for each ` x in R` .So dom (f) =R
` y =x^(2) rArr x = +- sqrt(y)`
when `y lt 0` there is no real value of x .So `y ge 0`
` :. ` range `(f) = R^(+)`


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