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Let `f(x) = x(2-x), 0 le x le 2`. If the definition of `f(x)` is extended over the set `R-[0,2]` by `f (x+1)= f(x)`, then f is aA. periodic function with period 1B. non-periodic functionC. periodic function with period 2D. periodic function with period `1//2` |
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Answer» Correct Answer - C For any `x in R -[0,2]` we have `f(x+2) = f((x+ 1)+1)` `rArr f(x+2) = f(x+1)" "[because f(x+1) = f(x)]` `rArr f(x+2) = f(x+1) " "[because f(x+1) = f(x)]` Therefore `f(x)` is periodic with period 2. |
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