Let f(x)=[x]+{x}^(3) then the area of the figure bounded by y=f^(-1)(x),y=0 between the ordinates x=2 and x=9/2 is alpha, then alpha-3/(2^(10//3))+1/2 is equal to ________(where [.] denotes the greatest integer function)

Let f(x)=[x]+{x}^(3) then the area of the figure bounded by y=f^(-1)(x

1.	Let f(x)=[x]+{x}^(3) then the area of the figure bounded by y=f^(-1)(x),y=0 between the ordinates x=2 and x=9/2 is alpha, then alpha-3/(2^(10//3))+1/2 is equal to ________(where [.] denotes the greatest integer function)
Answer» Solution :`f^(-1)(X)=[x]+{x}^(1//3)` So, `int_(2)^(9//2)[x]dx+int_(2)^(9//2){x}^(1//3)=17/2+3/(2^(10//3))`

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Let f(x)=[x]+{x}^(3) then the area of the figure bounded by y=f^(-1)(x),y=0 between the ordinates x=2 and x=9/2 is alpha, then alpha-3/(2^(10//3))+1/2 is equal to ________(where [.] denotes the greatest integer function)

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