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Let f(x)=x2−2|x| and g(x)=⎧⎪⎨⎪⎩min {f(t)},−2≤t≤x,−2≤x<0max {f(t)},0≤t≤x,0≤x≤2,f(x),x>2⎫⎪⎬⎪⎭ then g(x) is not differentiable at |
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Answer» Let f(x)=x2−2|x| and g(x)=⎧⎪⎨⎪⎩min {f(t)},−2≤t≤x,−2≤x<0max {f(t)},0≤t≤x,0≤x≤2,f(x),x>2⎫⎪⎬⎪⎭ |
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